fix: 战略地图P0修复 — KPI code统一+放开同层连线+数据迁移

2026-07-14 16:02:33 +08:00
parent c7d436ec7a
commit 6218a7d2db
8775 changed files with 4125 additions and 1758555 deletions
@@ -1,87 +0,0 @@
-# Copyright (c) 2010-2024 openpyxl
-
-from itertools import accumulate
-import operator
-import numpy
-from openpyxl.compat.product import prod
-
-
-def dataframe_to_rows(df, index=True, header=True):
-    """
-    Convert a Pandas dataframe into something suitable for passing into a worksheet.
-    If index is True then the index will be included, starting one row below the header.
-    If header is True then column headers will be included starting one column to the right.
-    Formatting should be done by client code.
-    """
-    from pandas import Timestamp
-
-    if header:
-        if df.columns.nlevels > 1:
-            rows = expand_index(df.columns, header)
-        else:
-            rows = [list(df.columns.values)]
-        for row in rows:
-            n = []
-            for v in row:
-                if isinstance(v, numpy.datetime64):
-                    v = Timestamp(v)
-                n.append(v)
-            row = n
-            if index:
-                row = [None]*df.index.nlevels + row
-            yield row
-
-    if index:
-        yield df.index.names
-
-    expanded = ([v] for v in df.index)
-    if df.index.nlevels > 1:
-        expanded = expand_index(df.index)
-
-    # Using the expanded index is preferable to df.itertuples(index=True) so that we have 'None' inserted where applicable
-    for (df_index, row) in zip(expanded, df.itertuples(index=False)):
-        row = list(row)
-        if index:
-            row = df_index + row
-        yield row
-
-
-def expand_index(index, header=False):
-    """
-    Expand axis or column Multiindex
-    For columns use header = True
-    For axes use header = False (default)
-    """
-
-    # For each element of the index, zip the members with the previous row
-    # If the 2 elements of the zipped list do not match, we can insert the new value into the row
-    # or if an earlier member was different, all later members should be added to the row
-    values = list(index.values)
-    previous_value = [None] * len(values[0])
-    result = []
-
-    for value in values:
-        row = [None] * len(value)
-
-        # Once there's a difference in member of an index with the prior index, we need to store all subsequent members in the row
-        prior_change = False
-        for idx, (current_index_member, previous_index_member) in enumerate(zip(value, previous_value)):
-
-            if current_index_member != previous_index_member or prior_change:
-                row[idx] = current_index_member
-                prior_change = True
-
-        previous_value = value
-
-        # If this is for a row index, we're already returning a row so just yield
-        if not header:
-            yield row
-        else:
-            result.append(row)
-
-    # If it's for a header, we need to transpose to get it in row order
-    # Example: result = [['A', 'A'], [None, 'B']] -> [['A', None], ['A', 'B']]
-    if header:
-        result = numpy.array(result).transpose().tolist()
-        for row in result:
-            yield row