"""auto_collect 复核闸门（kpi_review_gate.py）纯函数单测 — 2026-09-14

覆盖：阈值换算（金额/比率）、规则版本指纹、锚点判定、主值 remark 回写幂等与长度安全。
不连库（只构造 KPIValueSource 内存对象）。
"""
import os
import sys

sys.path.insert(0, os.path.dirname(os.path.dirname(os.path.abspath(__file__))))

from app.models import KPIValueSource  # noqa: E402
from scripts.kpi_review_gate import (  # noqa: E402
    RATIO_PP, _with_recheck_remark, anchor_check, rule_version, tolerance,
)


def _mapping(rule, unit=1.0, status="active", kpi_id=1):
    m = KPIValueSource()
    m.entity_id = 1
    m.kpi_id = kpi_id
    m.source_table = "voucher_details"
    m.source_field = "credit_amount"
    m.aggregate = "sum"
    m.period_field = "period"
    m.unit_conversion = unit
    m.status = status
    m.filter_rule = rule
    return m


def test_tolerance_amount_class():
    # 万元口径（unit=0.0001）：max(1000元, 0.5%×主值) → 换算回万元
    m = _mapping({"calc": "sum", "subject_codes": ["5001"]}, unit=0.0001)
    tol, cls = tolerance(m, 81.08)
    assert cls == "amount"
    assert abs(tol - 0.4054) < 1e-9          # 0.5%×810800元=4054元=0.4054万
    tol_small, _ = tolerance(m, 1.0)         # 主值 1 万元 → 0.5%=50元 < 下限 1000元
    assert abs(tol_small - 0.1) < 1e-9


def test_tolerance_ratio_class():
    m = _mapping({"calc": "ratio", "subject_codes": ["5001", "5401"]}, unit=1.0, kpi_id=2)
    tol, cls = tolerance(m, 0.05)
    assert cls == "ratio" and tol == RATIO_PP == 0.005
    # 0.34 个百分点在容差内、0.6 个百分点超容差
    assert abs(0.3766 - 0.38) <= tol
    assert abs(0.3860 - 0.38) > tol


def test_rule_version_stable_and_changes_on_rule_edit():
    r1 = {"calc": "sum", "subject_codes": ["5001"], "validation": {"matched": 3}}
    r2 = {"calc": "sum", "subject_codes": ["5001"], "validation": {"matched": 2}}
    v1a = rule_version(_mapping(r1))
    v1b = rule_version(_mapping(r1))
    assert v1a == v1b                       # 确定性 + validation 不参与指纹
    assert rule_version(_mapping(r2)) == v1a
    r3 = {"calc": "sum", "subject_codes": ["5001", "6001"], "validation": {"matched": 3}}
    assert rule_version(_mapping(r3)) != v1a  # 科目组合变更 → 版本变
    assert rule_version(_mapping({"version": 7, "calc": "sum"})) == "7"


def test_anchor_check_period_level():
    rule = {"calc": "sum", "validation": {"matched": 2, "ref_periods": ["2026-06", "2026-07", "2026-08"],
            "checks": [{"period": "2026-06", "match": True},
                       {"period": "2026-07", "match": False},
                       {"period": "2026-08", "match": True}]}}
    m = _mapping(rule, unit=0.0001, kpi_id=3)
    ok_07, detail_07, agg = anchor_check(m, "2026-07")
    ok_08, _, _ = anchor_check(m, "2026-08")
    ok_09, detail_09, _ = anchor_check(m, "2026-09")
    assert ok_07 is False and "match=False" in detail_07
    assert ok_08 is True                    # 该期锚点通过（规则级 matched=2/3 一并回报）
    assert agg == {"matched": 2, "anchors": 3}
    assert ok_09 is False and "无锚点记录" in detail_09


def test_main_remark_idempotent_and_bounded():
    seg = ("2026-09-14 voucher_details 复算一致(自动归集id=2128, Δ=0.0000, rule=1 v6eac76a3)"
           "；主值批次2026-08-24 15:50:01早于源同步2026-09-11 16:35:14(时点差,不改数)")
    once = _with_recheck_remark(None, seg)
    twice = _with_recheck_remark(once, seg)
    assert once == twice, "同一自动行重跑不得重复追加（否则撑爆 varchar(500)）"
    long_old = "旧正文" * 300                # 远超 500
    got = _with_recheck_remark(long_old, seg)
    assert len(got) <= 500 and got.endswith(seg)
    # 两条不同自动行的留痕都要在（不同 id → 不互相覆盖）
    seg2 = seg.replace("id=2128", "id=2129")
    both = _with_recheck_remark(once, seg2)
    assert "id=2128" in both and "id=2129" in both and len(both) <= 500